Basic algebra formulas that you can revise anytime and anywhere

FORMULAS FOR BEGINNER (a+b) ^2= a^2+b^2+2ab (a+b) ^2= (a-b) ^2+4ab (a-b) ^2= a^2+b^2-2ab (a-b) ^2= (a+b) ^2-4ab a^2+b^2= (a+b) ^2-2ab a^2+b^2= (a-b) ^2+ 2ab a^2-b^2= (a+b) (a-b) (a+b+c) ^2= a^2+b^2+c^2+2(ab+bc+ac) (a-b-c) ^2= a^2+b^2+c^2-2(ab-bc+ac) (a+b) ^3= a^3+b^3+3ab(a+b) (a-b) ^3= a^3-b^3+3ab(a-b) a^3+b^3= (a+b) (a^2-ab+b^2) a^3-b^3= (a-b) (a^2+ab+b^2) a^4-b^4= (a^2-b^2) (a^2+b^2) = (a^2+b^2) (a+b) (a-b) a^5+b^5= (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4) a^5-b^5= (a-b) (a^4+a^3b+a^2b^2+ab^3+b^4)

Pattern related coding





Print Pattern

#include < stdio.h >
int main()
{
int row, c, n, temp;
printf("Enter the number of rows in pyramid of stars you wish to see ");
scanf("%d",&n);
temp = n;
for ( row = 1 ; row <= n ; row++ )
{
for ( c = 1 ; c < temp ; c++ )
printf(" ");
temp--;
for ( c = 1 ; c <= 2*row - 1 ; c++ )
printf("*");
printf("\n");
}
return 0;
}


Diamond pattern

#include < stdio.h >
int main()
{
int n, c, k, space = 1;
printf("Enter number of rows\n");
scanf("%d", &n);
space = n - 1;
for (k = 1; k <= n; k++)
{
for (c = 1; c <= space; c++)
printf(" ");
space--;
for (c = 1; c <= 2*k-1; c++)
printf("*");
printf("\n");
}
space = 1;
for (k = 1; k <= n - 1; k++)
{
for (c = 1; c <= space; c++)
printf(" ");
space++;
for (c = 1 ; c <= 2*(n-k)-1; c++)
printf("*");
printf("\n");
}
return 0;
}


Print floyd's triangle

#include < stdio.h >
int main()
{
int n, i, c, a = 1;
printf("Enter the number of rows of Floyd's triangle to print\n");
scanf("%d", &n);
for (i = 1; i < n; i++)
{
for (c = 1; c < i; c++)
{
printf("%d ",a);
a++;
}
printf("\n");
}
return 0;
}


Print pascal triangle

#include < stdio.h >
long factorial(int);
int main()
{
int i, n, c;
printf("Enter the number of rows you wish to see in pascal triangle\n");
scanf("%d",&n);
for ( i = 0 ; i < n ; i++ )
{
for ( c = 0 ; c < = ( n - i - 2 ) ; c++ )
printf(" ");
for( c = 0 ; c < = i ; c++ )
printf("%ld ",factorial(i)/(factorial(c)*factorial(i-c)));
printf("\n");
}
return 0;
}
long factorial(int n)
{
int c;
long result = 1;
for( c = 1; c < = n; c++ )
result = result*c;
return ( result );
}


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