Basic algebra formulas that you can revise anytime and anywhere

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FORMULAS FOR BEGINNER (a+b) ^2= a^2+b^2+2ab (a+b) ^2= (a-b) ^2+4ab (a-b) ^2= a^2+b^2-2ab (a-b) ^2= (a+b) ^2-4ab a^2+b^2= (a+b) ^2-2ab a^2+b^2= (a-b) ^2+ 2ab a^2-b^2= (a+b) (a-b) (a+b+c) ^2= a^2+b^2+c^2+2(ab+bc+ac) (a-b-c) ^2= a^2+b^2+c^2-2(ab-bc+ac) (a+b) ^3= a^3+b^3+3ab(a+b) (a-b) ^3= a^3-b^3+3ab(a-b) a^3+b^3= (a+b) (a^2-ab+b^2) a^3-b^3= (a-b) (a^2+ab+b^2) a^4-b^4= (a^2-b^2) (a^2+b^2) = (a^2+b^2) (a+b) (a-b) a^5+b^5= (a+b) (a^4-a^3b+a^2b^2-ab^3+b^4) a^5-b^5= (a-b) (a^4+a^3b+a^2b^2+ab^3+b^4)
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Looking back on your last position , have you done your best work

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1.
Yes, I have done my best work. I was a good employee of my previous organisation. All qualities like dedication, punctuality and obedience made me to learn new values of life that should be taken care of.



2.
I always try to give my best to last company and always keep on trying to give my best in future also, because keep trying I can improve my mistake.



3.
Today's destiny are decided by past performance I am always trying to do my best to achieve good position.



4.
In my previous company I have been best at my work. I always try to do my best everywhere and I was recognized and awarded for my best performance.



5.
Yes, my work has been appreciated in writing.



6.
I gave my 2 years to my previous company with 100% result. After 1 month my boss call me and said to come in the office next day. I go and he want's that I should join again so this means that I gave my best to my company.



7.
Sir, I can only say that there is always a scope for improvement. So, I did the work in best possible way and my seniors were happy with my work.



8.
I can only say that, I had done work which was satisfied to my boss. He is very much satisfied with my work. And most important I was satisfied with my work.


9.
Today's my position is Example of my past performance and I believe that hard work is the only way to success.


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